mongodb - Query for documents where array size is greater than 1 -

i have mongodb collection documents in following format:

{   "_id" : objectid("4e8ae86d08101908e1000001"),   "name" : ["name"],   "zipcode" : ["2223"] } {   "_id" : objectid("4e8ae86d08101908e1000002"),   "name" : ["another ", "name"],   "zipcode" : ["2224"] } 

i can documents match specific array size:

db.accommodations.find({ name : { $size : 2 }}) 

this correctly returns documents 2 elements in name array. however, can't $gt command return documents name field has array size of greater 2:

db.accommodations.find({ name : { $size: { $gt : 1 } }}) 

how can select documents name array of size greater 1 (preferably without having modify current data structure)?

update:

for mongodb versions 2.2+ more efficient way described @johnnyhk in answer.

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1.using $where

db.accommodations.find( { $where: "this.name.length > 1" } ); 

but...

javascript executes more native operators listed on page, flexible. see server-side processing page more information.

2.create extra field namesarraylength, update names array length , use in queries:

db.accommodations.find({"namesarraylength": {$gt: 1} }); 

it better solution, , work faster (you can create index on it).