arrays - Why does read -a fail in zsh -

if type:

echo "1 dquote> 2 quick dquote> 3 brown" | while read -a d; echo "${d[1]}--${d[0]}"; done 

in bash says:

the--1 quick--2 brown--3 

but in zsh says:

zsh: bad option: -a 

why? , should instead?

in both shells read builtin. shares same purpose, implementation , options differ.

in order read in array in zsh, read requires option -a (instead of -a):

echo "1 2 quick    3 brown" | while read -a d; echo $d[2]--$d[1]; done  

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note: there many more differences between zsh , bash:

• in zsh arrays numbered 1 default, in bash start zero.
• echo $array prints outputs elements in zsh first element in bash
• to print third element of array in sh can use echo $array[3]. in bash braces needed delimit subscript, subscript third element 2: echo ${array[2]}.

• in zsh not need quote parameter expansions in order handle values white spaces correctly. example

  filename="no such file" cat $filename 

  will print 1 error message in zsh:

  cat: 'no such file': no such file or directory 

  but 3 error messages in bash:

  cat: no: no such file or directory cat: such: no such file or directory cat: file: no such file or directory 

• in zsh builtin echo evaluates escape codes default. in bash need pass -e argument that.

  echo 'foo\tbar' 

  zsh:

  foo     bar 

  bash:

  foo\tbar 

• …

generally, important keep in mind that, while zsh , bash similar, far being same.