assembly - Finding the minimum in an array (Intel8086) -

i'd write simple program find minimum value in array. i'm using intel 8086 architecture (if i'm right?). problem totally new assembly language , well, cannot figure out doing wrong in code, i'm stuck.

at end (before exiting) ax register not contain result.
i'm afraid doesn't place there (i check registers' values turbo debugger tool).

.model tiny  data segment                         arr_len     equ 5                         arr         db 07h, 02h, 03h, 10h, 12h                         minimum     db 255 data ends  code segment                         org 100h                         assume cs:code, ds:data, ss:code start:                         mov ax, seg data                         mov ds, ax  ;load data ds reg                             mov cx, arr_len ;arr_length counter                         mov bx, offset arr ;load first elem. search:                          inc bx                         cmp bl, [minimum] ;compare loaded elem min                         jb swap ;if bl<minimum swap:                         mov minimum, bl                         loop search                                   mov al, minimum ;result here?                         mov ax, 4c00h                         int 21h  code ends end start 

could give me advices wrong here? in advance.

• the tiny model doesn't need setting ds explicitly. (cs=ds=es=ss)
• since bx points @ array first time, should not increment it! inc before looping only.
• you didn't compare array element rather low byte of address iterate array.
• there's no sense in putting result in al if directly afterwards exit putting 4c00h in ax. viewing al using debugger work though.

here's version can work:

search:      mov al, [bx]     cmp al, [minimum] ;compare loaded elem min     jnb noswap        ;if al>=minimum     mov [minimum], al ;new minimum noswap:     inc bx     loop search