i'm trying change result if there 2 grades in values replace 2 grades average. tried many techniques failed. need write solution average , delete 2 values of grades.
i wrote code:
def mydict(grades, teachers): dict={} i1 in grades: i2 in teachers: key=i2[1] value=[] dict[key]=value #{'statistics': [], 'philosophy': [], 'computer': [], 'physics': [], 'english': []} i1 in grades: if key==i1[-1]: value.append(i1[0]) #{'statistics': [23560, 23452], 'philosophy': [], 'computer': [23415, 12345], 'physics': [23452, 23459], 'english': [12345]} i1 in grades: if key==i1[-1]: value.append(i1[1]) value_size=len(value) if value_size>2: end=int(value_size)/2 in value[-1:end]: print float(count(i)/value_size) print dict grades = [[12345,75,'english'], [23452,83,'physics'], [23560,81,'statistics'], [23415,61,'computer'], [23459,90,'physics'], [12345,75,'computer'], [23452,100,'statistics']] teachers = [['aharoni','english'], ['melamed','physics'], ['kaner','computer'], ['zloti','statistics'], ['korman','philosophy']] print mydict(grades, teachers) the result is:
>>> {'statistics': [23560, 23452, 81, 100], 'philosophy': [], 'computer': [23415, 12345, 61, 75], 'physics': [23452, 23459, 83, 90], 'english': [12345, 75]} none >>> what want (it in process, stuck in level):
{ 'aharoni': [12345, 75.0], 'kaner': [23415, 12345, 68.0], 'melamed': [23452, 23459, 86.5], 'korman': [], 'zloti': [23560, 23452, 90.5] }
what simple loop:
mydict = {} teacher, subject in teachers: values = [] scores = [] i1, i2, s in grades: if subject == s: values.append(i1) scores.append(i2) if scores: average = sum(scores) / len(scores) values.append(average) mydict[teacher] = values first, iterate trough teachers, , each matching subject in grade list, append i1 , i2 list.
at end of iteration, can compute average of i2 values (if list not empty) , update dictionnary.
the output data be:
{ 'korman': [], 'melamed': [23452, 23459, 86.5], 'zloti': [23560, 23452, 90.5], 'aharoni': [12345, 75.0], 'kaner': [23415, 12345, 68.0] } 
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