java - Split map into two lists -

i have map<string,integer> , it's sorted value this:

set = map.entryset(); list = new arraylist<map.entry<string, integer»(set); collections.sort( list, (o1, o2) -> (o2.getvalue()).compareto( o1.getvalue() )); 

i have sorted integer list map:

word_used = new arraylist<integer>(map.values()  .stream()  .sorted()  .collect(collectors.tolist()));  collections.reverse(word_used);  

but how can string list, sorted equal map (by value)?

i mean if have map items:

map.put("eggs",1500);  map.put("echo",150);  map.put("foo",320);  map.put("smt",50);  

and sort like:

eggs : 1500  foo : 320  echo : 150  smt : 50  

i need 2 lists:

eggs  foo  echo  smt 

and

1500  320  150  50 

you can add projection streams using map(), this:

list<string> word_used = map.entryset()          .stream()          .sorted(comparator.comparing(map.entry<string,integer>::getvalue).reversed())         .map(map.entry<string,integer>::getkey)         .collect(collectors.tolist());  list<integer> ints_used = map.entryset()          .stream()          .sorted(comparator.comparing(map.entry<string,integer>::getvalue).reversed())         .map(map.entry<string,integer>::getvalue)         .collect(collectors.tolist()); 

demo 1

note approach sorts twice. can capture entries once, , project temporary list, this:

list<map.entry<string,integer>> sortedlist = map         .entryset()          .stream()          .sorted(comparator.comparing(map.entry<string,integer>::getvalue).reversed())         .collect(collectors.tolist());  list<string> word_used = sortedlist         .stream()         .map(map.entry<string,integer>::getkey)         .collect(collectors.tolist());  list<integer> ints_used = sortedlist         .stream()         .map(map.entry<string,integer>::getvalue)         .collect(collectors.tolist()); 

demo 2