Python Password Program -

i'm beginner programmer , thought cool create program loop through "all" possible passwords. on scale of 1-10, how efficient rate following "hacking program?" there way make following code more efficient? algorithms or tricks may know of?

i've considered moving 'e' , more common letters beginning of character array since letters used more commonly.

import sys  password = raw_input("enter password: ")  characters = [] lower = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] upper = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] number = ["1","2","3","4","5","6","7","8","9","0"] symbol = ["!","@","#","$","%","^","&","*","(",")","_","+","-","="]  #creates array keyboard characters in range(len(lower)):     characters.append(lower[i]) in range(len(upper)):     characters.append(upper[i]) in range(len(number)):     characters.append(number[i]) in range(len(symbol)):     characters.append(symbol[i])  found = false  #for 1 character passwords in range(len(characters)):     if (characters[a] == password):         print (characters[a])         found = true if (found):     sys.exit()  #for 2 character passwords in range(len(characters)):     b in range(len(characters)):         if (characters[a] + characters[b] == password):             print (characters[a] + characters[b])             found = true if (found):     sys.exit()  in range(len(characters)):     b in range(len(characters)):         c in range(len(characters)):             if (characters[a] + characters[b] + characters[c] == password):                 print (characters[a] + characters[b] + characters[c])                 found = true if (found):     sys.exit()  in range(len(characters)):     b in range(len(characters)):         c in range(len(characters)):             d in range(len(characters)):                 if (characters[a] + characters[b] + characters[c] + characters[d] == password):                     print (characters[a] + characters[b] + characters[c] + characters[d])                     found = true if (found):     sys.exit()  in range(len(characters)):     b in range(len(characters)):         c in range(len(characters)):             d in range(len(characters)):                 e in range(len(characters)):                     if (characters[a] + characters[b] + characters[c] + characters[d] + characters[e] == password):                         print (characters[a] + characters[b] + characters[c] + characters[d] + characters[e])                         found = true if (found):     sys.exit() 

first of all, didn't have type symbols

>>> import string >>> string.uppercase 'abcdefghijklmnopqrstuvwxyz' >>> string.lowercase 'abcdefghijklmnopqrstuvwxyz' >>> string.digits '0123456789' >>>  

so can do:

lower = string.lowercase 

and forth

this can go away:

#creates array keyboard characters in range(len(lower)):     characters.append(lower[i]) in range(len(upper)):     characters.append(upper[i]) in range(len(number)):     characters.append(number[i]) in range(len(symbol)):     characters.append(symbol[i]) 

and replaced with:

characters = "".join(upper, lower, number, symbol) 

this can simplified:

#for 1 character passwords in range(len(characters)):     if (characters[a] == password):         print (characters[a])         found = true if (found):     sys.exit() 

to:

for in characters:     print     sys.exit() 

the multi-character checks need loop, try writing loops showed in single character code above